Paulo is using a AWG 8 wire in a commercial retail install. What's the diameter in mils of the wire he’s putting in?

(2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)-x(x^2-9)^(1/3) (x^2+4)^((-1)/2))/(x^2+4)

and -x(x^2-9)^(1/3) (x^2+4)^((-1)/2)

(2/3 (x^2+4)^(1/2) (x^2-9)^((-2)/3)-x(x^2-9)^(1/3) (x^2+4)^((-1)/2))/(x^2+4)

and -x(x^2-9)^(1/3) (x^2+4)^((-1)/2)

Dividing the first term with the denominator (x^2+4), you get: 2/3 (x^2+4)^(-(1)/2) (x^2-9)^((-2)/3)

Dividing the first term with the denominator (x^2+4), you get: 2/3 (x^2+4)^(-(1)/2) (x^2-9)^((-2)/3)

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Dsolubility let me know if you have any other questions for chemistry