Una porción de 50.0 mL de una disolución que contiene 0.200 g de BaCl2·2H2O es mezclada con 50.0 mL de una disolución que contiene 0.300 g de NaIO3. Suponga que la solubilidad del Ba(IO3)2 en agua es insignificante y calcule a)la masa del precipitado Ba(IO3)2. b) la masa del compuesto sin reaccionar que permanece en disolución.

Explanation:

black pink in your area.

*tilts head* sounds more like a statement

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j