Please Help No Scammers, Using a two cell reduction potential shown for their corresponding reaction calculate the cell potential for a voltaic cell made from these two metals. Cu+2 + 2e Cu E = 0.52 V

Ag+1 + 2e Ag E = 0.80 V

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

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