How does 0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution?

0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution has a mass ratio of 2: 1

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Molarity shows the number of moles of solute in every 1 liter of solution.

m = Molality

n = Number of moles of solute

p = Solvent mass (gram)

The mole fraction shows the mole ratio of a substance to the mole of solution / mixture

nA + nB = 1

There are 0.5 m sucrose (molecular mass 342) solution and 0.5 m glucose (molecular mass 180)

Then the comparison of the two is from the ratio of mass (assuming the mass of the solvent is equal to 1 kg)

Sucrose (C₁₂H₂₂O₁₁) 0.5 molal then the mass:

mass = 0.5 m x 342 = 171 grams

Glucose (C₆H₁₂O₆) 0.5 molal then the mass:

mass = 0.5 m x 180 = 90 grams

So the mass ratio = 171: 90 = 1.9: 1 or we round it to 2: 1

the molality of the solution

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the difference between molarity and molality

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Keywords: molality, glucose, sucrose, mass, solvent,

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be