For the reaction:
6li(s)+n2(g)→2li3n(s)
determine:
the mass of n2 needed to react with 0.536 moles of li.
the number of moles of li required to make 46.4 g of li3n.
the mass in grams of li3n produced from 3.65 g li.
the number of moles of lithium needed to react with 7.00 grams of n2.

Explanation:

1. Mass of needed to react with 0.536 moles of Li.

According to reaction, 6 moles of Li reacts with 1 mol of .

Then 0.536 moles of Li will react with:

moles of that is 0.0893 moles.

Mass of

2.The number of moles of Li required to make 46.4 g of

Moles of

According to reaction the 2 moles of are produced from 6 moles of Li.

Then 1.3257 moles of will produced from:

3.9771 moles of lithium will needed.

3. The mass in grams of produced from 3.65 g Li.

Moles of Li

According to reaction, 6 moles of Li gives 2 moles of

Then 0.5214 moles of Li will give that is 0.1738 moles of .

Mass of

6.083 grams of will be produced.

4. The number of moles of lithium needed to react with 7.00 grams of .

Moles of

1 mol of reacts with 6 mol of Li

Then, 0.25 moles of will ftreact with :

of lithium

1.5 moles of Li will be needed.

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