An experiment produced 0.10 g co2, with a volume of 0.056 l at stp. if the accepted density of co2 at stp is 1.96 g/l, what is the approximate percent error?

According to the accepted density of CO2, we can get that 0.10 g CO2 has a volume of 0.10/1.96=0.051 L (theoretical value). The percent error = (0.056 - 0.051)/0.051 * 100% = 9.80%.

Ais the correct answer