In a plant, 1,500 kg of nitrogen oxide is consumed per day to produce 1,500 kg of nitrogen dioxide per day. what is the percent yield?
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Molecular weight of Nitrogen Oxide, NO 
14g/mol N + 16g/mol O = 30 g/mol NO

Molecular weight Nitrogen Dioxide, NO2
14g/mol N + 2(16g/mol O) =  46g/mol NO2

Calculate mole NO
1,500 kg × (1,000g / 1kg) × (1mol / 30 g NO) = 50,000 mol NO

Calculate theoretical yield for the product NO2 ; assuming 1:1 stoichiometry.
50,000 mol × (46 g / mol NO2) × (1kg / 1,000g) = 2,300 kg NO2

Percent yield = 100 × (actual yield / theoretical yield)
100 × (1,500kg / 2,300kg) = 65%

Answer is to avoid experimental error