For a 0.50 molal solution of sucrose in water, calculate the freezing point and the boiling point of the solution. list each step.

We can solve for the freezing point and the boiling point of the solutions by using the freezing point depression and boiling point elevation formulas.

ΔTb = Kb m i

ΔTf = Kf m i

where,

Kb and Kf are the boiling point and freezing point constants for water

Kb = 0.51 °C / molal

Kf = - 1.86 °C / molal

m = molality = 0.50 molal

i = vant Hoff factor = 1

The freezing point and boiling points are:

Freezing point = 0°C + ΔTf

Freezing point = 0°C + (-1.86 °C / molal * 0.5 molal)

Freezing point = - 0.93 °C

Boiling point = 100°C + ΔTb

Boiling point = 100°C + (0.51 °C / molal * 0.5 molal)

Boiling point = 100.255°C

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

the answer is the first option

explanation:

just googled it m8. not that hard

lol