Chemistry, 03.01.2020 10:31 pikapika24

He fuel used in many disposable lighters is liquid butane, c4h10. butane has a molecular weight of 58.1 grams in one mole. how many carbon atoms are in 1.50 g of butane?

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molecular weight of C4H10 is = 58.1 grams

moles of butane = $\frac{1.5}{58.1}$ = 0.0258

Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:

0.0258 x 6.023 x 10^{23} molecules of butane = 1.5538 * 10^22 molecules
of butane

Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the

so, no. of carbon atoms = 4 x 1.5538 x 10^22 = 6.21 x 10^22 atoms

Answer from: stace49

6,237.10²² atoms are in 1.50 g of butane

Further explanation

Stokiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

In stoichiometry therein includes

1. the relative atomic mass (Ar) is a measurement of the mass of an atom relative to the mass of 1 carbon-12 atom 2. The relative molecular mass (M) is the sum of the mass of all the atomic masses that make up the molecule or is the sum of the relative atomic masses that make up the molecule

M X = (average mass of 1 molecule AxBy) / 1/12 mass 1 atom C-12

M AxBy = (x.Ar A + y. Ar B)

3. Mole is a unit of the number of particles where 1 mole is the number of particles contained in a substance (atom, molecule)which is equal to atoms in 12 gr C-12

1 mol = 6.0210²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) by the relative mass of the element (Ar) or the relative molecular mass (M)

mole = gram / (Ar / M)

For example

1 mole of H element contains 6.02 × 10²³ H atoms

1 mole of water contains 6.02 × 10²³ water molecules.

1 mole of KCl ion contains 6.02 × 10²³ K⁺ ions and 6.02 × 10²³ Cl⁻ ions.

We know Butane molar mass = 58 grams / mol and mass known to be 1.5 grams so the number of moles:

mole = gram / M

mole = 1.5 / 58

mole = 0.0259

So the number of moles of C atoms in Butane is:

= 4 (valence C) x number of moles of Butane

= 4. 0.0259