1.) which kind of bond would be expected from the above below? (1st image)

2.) which kind of bond would be expected from the above example? (2nd image)

3.) in order for carbon to obtain the inert gas configuration, it must gain or lose (6, 2, 4)valence electrons.

Image #1 is clearly sharing their electrons to complete an octet, which makes me believe it is a Double Bond.
Image #2 is a duplicate (if my computer is displaying this picture correctly) which if this is the case and my computer isn't the issue I'd say it is a Double Bond. I don't think "above" and "below" make a difference but it may depend on the attachments and where they were originally placed. Either way Image #1 and #2 are Double Bonds.

Image #3 if I recall accurately is where 4 valence electrons must be gained. I'm a bit fuzzy with valence electrons and recommended viewing Crash Course on this if you'd like to perfect your understanding on Valence Electrons, but I recall a similar question and I remember 4 valence electrons for this type of image. Wish I could help more on this. :(

Mark Brainliest/Like ;)

for the question

"In order for carbon to obtain the inert gas configuration, it must gain or lose  (2,4, or 6) valence electrons."

The answer is 4 electrons

Explanation:

Carbon has only four valence electrons and in order to get the nearest inert gas configuration it either has to accept four electrons or lose four electrons.

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.