An object is dropped onto the moon (g m = 5 ft/s 2 ). how long does it take to fall from an elevation of 250 ft.?

To determine the time needed in order for the object to reach a certain elevation we use the equation,
 
   d = V₀t + 1/2(gt²)

where d is the distance,
V₀ is the initial velocity which is equal to zero because the object is simply dropped
g is the acceleration due to gravity, and 
t is the time

If we derive the equation in order to solve for t, we have,
 
     t = sqrt ((2d/g))

If we convert the given in SI units,
   d = (250 ft) x (0.3048 m/ 1 ft) = 76.2 m
   g  = (5 ft/s²)(0.3048 m/ 1 ft) = 1.524 m/s²

Substitute,
 
      t = sqrt ((2)(76.2 m)/(1.524 m/s²))
      t = 10 s

Therefore, it will take 10 s for the object to be dropped to a distance of 250 ft. 

257 grams h2o i think

Ch4 and ph3 are both covalent since they are composed both of non-metals.    ch4 is non- polar because of  london forces and has a geometry of tetrahedral  ph3 , on the other hand, is umbrella shaped polar and has dipole-dipole intermolecular force (imf) . since ph3 is polar, it has a stronger imf