An aqueous solution contains 0.050 m of methylamine. the concentration of h+ in this solution is m. kb for methylamine is 4.4 × 10-4.

Methylamine is an amine which is an organic weak base. Its chemical formula is CH₃NH₂. When it undergoes hydrolysis wherein water is acting as an acid, the reaction would be

 CH₃NH₂ + H₂O ⇆  CH₃NH₃ + OH⁻

Then, we use the ICE analysis which stands for Initial-Change-Equilibrium.

                         CH₃NH₂ + H₂O ⇆  CH₃NH₃ + OH⁻
Initial                    0.05          -                 0         0
Change                 -x                              +x       +x

Equilibrium         0.05-x                           x          x

Then, we use the equation for the equilibrium constant of basicity.

Kb = [CH₃NH₃][OH⁻]/[CH₃NH₂] = 4.4×10⁻⁴
4.4×10⁻⁴ = [x][x]/[0.05-x]
[x] = 4.4756×10⁻³

The variable x here denotes the number of moles of the substance that is involved in the reaction. Since the equilibrium amount of OH⁻ is equal to x, then the concentration of OH⁻ is also 4.4756×10⁻³. Thus, 

pOH = -log[OH⁻]
pOH = -log[4.4756×10⁻³] = 2.35
The relationship between pOH and pH is that pH + pOH = 14. Thus,
pH = 14 - 2.35 = 11.65

pH = -log[H⁺]
11.65 = -log[H⁺]
[H⁺] = 2.234 × 10⁻¹² M

1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)