Determine the poh of a solution with the following 8.3*10^-7 m and classify the solution as acidic basic or neutral

One information is missing: the variable whose concentration is 8.3 * 10^-7 M.

There are two reasonable possibilities: 1) it is [H+] = [H3O+], or 2) it is [OH-]

So, I will do the problem with the two possibilities:

1) [H+] = [H3O+] = 8.3 * 10 ^ -7 M

=> pH = log  { 1 / [H+] } = log { 1 / (8.3 * 10^-7) } = 6.08

=> pOH = 14 - 6.08 = 7.92

And the solution is acidic (pH < 7 => acid)

2) [OH-] = 8.3 * 10^ -7

=> pOH = log { 1 / [OH-] } = log { 1 / (8.3 * 10 ^ -7) } = 6.08

=> pH = 14 - 6.08 = 7.92

=> The solution is basic (pH > 7 => basic)

2licl + 3o2 i yook the test and it was correct.