Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kj of heat. the bomb calorimeter has a mass of 1.30 kg and a specific heat of 3.41 j/(gi°c). if the initial temperature of the calorimeter is 25.5°c, what is its final temperature? use mc026-1.jpg. 30.9°c 34.5°c 44.0°c 51.5°c

Answer : The correct option is,

Explanation :

Formula used :

where,

= heat released = 24 KJ

= mass of bomb calorimeter = 1.30 Kg

= specific heat =

= final temperature = ?

= initial temperature =

Now put all the given values in the above formula, we get  the final temperature of the calorimeter.

Therefore, the final temperature of the calorimeter is,

Final temperature is 30,9°C

Explanation:

A bomb calorimeter is an instrument that allows the determination of the heat of combustion of a reaction. The heat q is defined as:

q = C×m×ΔT (1)

Where:

C is specif heat of calorimeter (3,41 J/g°C)

m is mass (1,3kg ≡ 1300g)

And ΔT is final temperature - initial temperature (X-25,5°C) X is final temperature

And q is heat (24,0kJ ≡ 24000J)

Replacing in (1):

24000J = 3,41J/g°C×1300g×(X-25,5°C)

5,41 = X-25,5°C

25,5°C + 5,41 = X

30,91°C = X

Final temperature is 30,9°C

I hope it helps!

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.