If the solubility of agno3 is 63.7g/100 ml water and you have 5.77 g dissolved in 10 ml of water is your solution unsaturated, saturated, or super saturated? explain and describe how this solution would look.

1) Concentration of AgNO3 in solution:

5.77 g / 10 ml = 0.577 g / ml

Multiply by 100 both numerator and denominator to obtain: 57.7 g / 100 ml.

2) Comparisson with the solubility

57.7 g / 100 ml < 63.7 g / 100 ml => the solution contains less AgNO3 than what it can dissolve according to its solubility.

Therefore, the solution is unsaturated.

U whay do you need with?

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.