Agran plot for a potentiometric titration resulted in a slope of 5.56 x 105. measurements were made using sce as the reference electrode and the analyte eo was determined to be 0.354 v. how many electrons are involved in the analyte oxidation/reduction?

We are given
s = 5.56 x 10^5
Eo = 0.354 V

We are asked how many electrons were involved in the redox reaction.

We use the Nernst Equation
Eo = s log [H+]
Subsituting
0.354 = 5.56 x 10^5 log [H+]
[H+] = 1 mole/L

Assuming that we have a 1 L volume, we have 1 mole of H+ that participates in the reaction which means there is also 1 mole of electron that is involved in the reaction.

Bis the answerhope it !