An ion has 12 protons, 14 neutrons, and 10 electrons. the symbol for the ion is

The symbol for the ion is Mg²⁺

From the question given above, the following data were obtained:

Proton = 12

Neutron = 14

Electron = 10

Next, we shall determine the atomic number of the ion.

The atomic number of an element is simply the number of protons in the atom of the element.

Proton = 12

Thus, the ion is magnesium (Mg) ion since only magnesium has atomic number of 12

Finally, we shall determine the charge on the ion. This can be obtained as follow:

Proton = 12

Electron = 10

Charge = Proton – Electron

Charge = 12 – 10

Therefore, the symbol of the ion is Mg²⁺

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in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm