How many grams of magnesium oxide can be produced when 125 g mg react with 102 g o2?

unbalanced equation: mg + o2 → mgo

show, or explain, all of your work along with the final answer.

The balanced chemical reaction is 

2Mg + O2 → 2MgO

To determine the amount of magnesium oxide produced from the reaction, we use the initial amount of the reactants and the relation of the substances from the reaction. We do as follows:

125 g Mg ( 1 mol / 24.31 g ) = 5.14 mol Mg
102 g O2 ( 1 mol / 32 g) = 3.19 mol O2

Therefore, the limiting reactant is magnesium. We calculate as follows:

5.14 mol Mg ( 2 mol MgO / 2 mol Mg ) ( 40.31 g /mol) = 207.19 g MgO produced.

4- c, because all matter stays the same no matter what. it is still there. 5- b, because matter is known as mass. 6-c because, flammability is a chemical property. malleability is changing the shape of an object.

You use the atomic number to find out how many protons and neutrons there are in the atom. you use the atomic mass to find out how many protons and electrons there are in the atom.