Given the following reactions and subsequent ∆h values what is the ∆h for the reaction below?
zn(s) + 1/8s8(s) + 2o2(g) → znso4(s)

given:
zn(s) + 1/8s8(s) → zns(s)
∆h = -183.92kj

2zns(s) + 3o2(g) → 2zno(s) + 2so2(g)
∆h = -927.54kj

2so2(g) + o2(g) → 2so3(g)
∆h = -196.04kj

zno(s) + so3(g) → znso4(s)
∆h = -230.32kj

answers options:
a) 244.01 kj
b) 488.02 kj
c) -488.02 kj
d) -976.03 kj
e) 976.03 kj