What is the overall cell potential for this redox reaction?
ba + ca2+ → ba2+ + ca
given: ba2+ + 2e− → ba(s) –2.90 and ca2+ + 2e− → ca(s) –2.87

Explanation:

It is known that in an electrochemical cell, chemical reaction occurring at the electrodes generates a potential difference.

In an electrochemical cell, oxidation process occurs at anode and reduction process occurs at cathode.

For example,

Cathode:

Anode :

Also, it is known that when more negative is the value of more easily an atom can lose electrons. Hence, oxidation will occur where value is more negative.

Thus, calculate the overall cell potential as follows.

                          = -

                               = [-2.87 - (-2.90)] V

                               = 0.03 V

Thus, we can conclude that overall cell potential for the given redox reaction is 0.03.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.