What is the empirical formula of a phosphoric acid that contains 0.3086 g of hydrogen, 3.161 g of phosphorus, and 6.531 g of oxygen?

M(H)=1.008 g/mol
M(P)=30.974 g/mol
M(O)=15.999 g/mol

n(H)=m(H)/M(H)
n(H)=0.3086/1.008=0.3062 mol

n(P)=m(P)/M(P)
n(P)=3.161/30.974=0.1021 mol

n(O)=m(O)/M(O)
n(O)=6.531/15.999=0.4082 mol

H:P:O = 0.3062:0.1021:0.4082 ≈ 3 : 1 : 4

H₃PO₄

The answer would be

Q2eqefefgvsdfvfefsvsdvcwef