Consider the reaction below. 2al2o3 4al + 3o2 how many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed? 17.7 mol 19.9 mol 39.8 mol 53.0 mol

 The moles  of  oxygen  that are produced when 26.5 mol  of Al2O3  decomposes  is  39.8 mol

calculation

2Al2O3  + 4Al +3 O2

Answer : The number of moles of oxygen produced are, 39.8 mole

Solution : Given,

Moles of aluminium oxide = 26.5 mole

The given balanced chemical reaction is,

From the balanced chemical reaction, we conclude that

As, 2 moles of aluminium oxide decomposes to give 3 moles of oxygen

So, 26.5 moles of aluminium oxide decomposes to give moles of oxygen

Therefore, the number of moles of oxygen produced are, 39.8 mole

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied