Aforce of 2,500 pounds drags a truck 30 feet in 1/2 minute.
how much work is accomplished and how much power was required?

you for whoever can me

i'm not sure why science isn't an option so i put chemistry

The right subject for this question is physics.

To calculate the work you use the formula:

Work = force * displacement

Work = 2500 pounds * 30 feet = 75,000 pounds - feet

To calculate the power you use the formula:

power = work / time

Power = 75,000 pound - feet / 30 seconds = 2300 pound-feet / second.

I'm into politics, why am i getting these questions? it's 4: 30 am in texas. my paper is due in 2 days. i'm the one needing in political science

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer