Astandard solution of 0.243 m naoh was used to determine the concentration of a hydrochloric acid solution. if 46.33 ml of naoh is needed to neutralize 10.00 ml of the acid, what is the molar concentration of the acid?

The reaction of NaOH and HCl is as follows: NaOH+HCl⇒NaCl+H2O.  So the ratio between the two reactants is NaOH:HCl=1:1.  According to the question, the moles of NaOH needed to neutralize the acid is 0.243M*0.04633L=0.01126mole. Because is the above ratio (1:1), the moles of acid that are being neutralized is also 0.01126mole.  So the concentration of the acid is 0.01126mole/0.010L = 1.126 M.

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