Agas in a rigid container at 25°c has a pressure of 0.96 atm. a change in temperature causes the pressure to increase to 1.25 atm. what is the new temperature of the gas?

The new temperature  of the gas is  388.02 k  or 115.02°c

 calculation

The  new temperature  is calculated  using Gay Lussac's   formula

That is P₁/T₁ = P₂/T₂

where;

P₁  = 0.96 atm

T₁ = 25°c into kelvin   = 25 +273  =298 k

P₂= 1.25 atm

T₂ =  ?  k

make T₂ the subject of the formula

T₂ = P₂T₁/P₁

 = (1.25 atm x 298 k) / 0.96 atm  =  388.02 K   or  388.02 -273 =115.02°c

imma come back to you hold on