What is the empirical formula of a compound that is 62.0% c, 10.4% h, and 27.5% o by mass?

The empirical formula for the given compound is

Explanation:

We are given:

Percentage of C = 62.0 %

Percentage of H = 10.4 %

Percentage of O = 27.5 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 62.0 g

Mass of H = 10.4 g

Mass of O = 27.5 g

To formulate the empirical formula, we need to follow some steps:

Moles of Carbon =

Moles of Hydrogen =

Moles of Oxygen =

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.72 moles.

For Carbon =

For Hydrogen  =

For Oxygen  =

The ratio of C : H : O = 3 : 6 : 1

Hence, the empirical formula for the given compound is

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.