If 10.5 g copper chloride react with 12.4 g aluminum what is the limiting reactant

copper chloride

Explanation:

From the balanced equation. it can be seen that 3 moles of copper chloride reacts with 2 moles of Al.

Thus 0.08 moles of copper chloride reacts with= moles of Al.

Thus copper chloride is the limiting reagent as it limits the formation of product and aluminium is the excess reagent as it is left unused. (0.46-0.05)=0.41 moles are in excess.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o