How many grams of oxygen are needed to react completely with 200.0 g of ammonia, nh3? 4nh3(g) + 5o2(g) ? 4no(g) + 6h2o(g)?

Answer : The mass of oxygen needed are 470.592 grams.

Solution : Given,

Mass of = 200.0 g

Molar mass of = 17 g/mole

Molar mass of = 32 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of  

The balanced chemical reaction is,

From the reaction, we conclude that

As, 4 mole of react with 5 mole of

So, 11.765 moles of react with moles of

Now we have to calculate the mass of

Therefore, the mass of oxygen needed are 470.592 grams.