Bf3 + li2so3 > b2(so3)3 + lif what is the coefficient of lithium fluoride in the balanced chemical reaction?
1
3
4
6

Ans) 6

The given equation is:

BF3 + Li2SO3 → B2(SO3)3 + LiF

# atoms in Reactants                                    # atoms in Products

B = 1                                                                   B = 2

F = 3                                                                   F = 1

Li = 2                                                                  Li = 1

S = 1                                                                    S = 3

O = 3                                                                   O = 9

In order to balance the unequal distribution of atoms, multiply BF3 by 2,  Li2SO3 by 3 and LiF by 6 to get:

2BF3 + 3Li2SO3 → B2(SO3)3 + 6LiF

Coefficient of LiF = 6

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