Question 8

match each chemical reaction to its type:

c3h8 + 5 o2 --> 3 co2 + 4 h2o

2 h2o2 --> 2 h2o + o2

agno3 + kbr --> agbr + kno3

cucl2 + zn --> zncl2 + cu

cao + h2o --> ca(oh)2

a.
decomposition

b.
combustion

c.
double replacement

d.
single replacement

e.
synthesis

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2