Pure acetic acid has a density of 1.049 g/ml calculate the molarity of pure acetic acid

Molarity = mol/L

density= grams/ mL

this is a conversion problem where we have to change the numerator from grams to moles, and the denominator from ml to L.

First, we need our conversion factors

1 liters= 1000 mililters

to convert the mass to moles, we need the molar mass of the compound acetic acid (CH3COOH)

molar mass of CH3COOH is 60.05 g/mol, which can be calculated by going to the periodic table and add the mass of the each atom in the compound formula. 

1.049 g/ ml (1 mol/ 60.05 grams)= 0.0175 mol/ ml

0.0175 mol/ ml (1000 ml/ 1 liters)= 17.5 mol/ L or 17.5 M

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