The bond dissociation enthalpies of the h–h bond and the h–cl bond are 435 kj mol–1 and 431 kj mol–1 , respectively. the ∆hºf of hcl(
g. is –92 kj mol–1 . what is the bond dissociation enthalpy of the cl–cl bond?

First, we write the reaction equation for the formation of HCl from hydrogen and chlorine:
H₂ + Cl₂ → 2HCl

Now, we substitute the values of the enthalpies, denoting that of the Cl-Cl bond by x:
435 + x = -92 + 2(431)
x = 335
The bond dissociation enthalpy for the Cl-Cl bond is 335 kJ/mol