How many grams of potassium nitrate (kno3) would form if 2.25 liters of a 1.50 molar lead nitrate pb(no3)2 solution reacts with 1.15 liters of a 2.75 molar potassium chromate k2cro4 solution? pb(no3)2 + k2cro4 pbcro4 + 2kno3 108 g 681 g 639 g 362

a. a clone will be physically identical to the original, but won’t be genetically identical

have a good day!

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%