An average adult has a total lung capacity of 6.0 l. how many total grams of air could be held in the lungs at a pressure of 102 kpa and a normal body temperature of 37° celsius? (assume that the average molar mass of air is 29 g/mol.)

The amount of air that could be held in lungs is 6.873g

Explanation:

To calculate the amount of air, we use the equation given by Ideal gas equation, which follows:

where,

P = Pressure of the gas = 102 kPa

V = volume of the gas = 6 L

n = number of moles of gas = ? mol

R = Gas constant =

T = temperature of the gas = 37°C = 310 K  (Conversion factor:

Putting values in above equation, we get:

To calcultae the mass of the air, we use the equation:

We are given:

Moles of air entered = 0.237 mol

Molar mass of air = 29 g/mol

Putting values in above equation, we get:

Hence, the amount of air that could be held in lungs is 6.873g

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.