Calculate the boiling point of a 1.5 m aqueous solution of nacl. the boiling point constant of water is 0.512 °c/m. remember, m is a unit for molality.
a.98.5 °c
b.100.0 °c
c.100.8 °c
d.101.5 °c

To determine boiling point, we have the equation: ΔT = mK; where ΔT refers to the boiling-point elevation, m refers to molality which is in the unit mol/kg, and K is the molal boiling-point elevation constant.

In this problem, water is the solvent and NaCl is the solute. Note that 100°C is the boiling point of water. We substitute the equation:
ΔT = (1.5 m)(0.512 °C/m) 
ΔT = 0.768°C
This is the change in temperature. To find the boiling point of the whole solution, we add the boiling point of the solvent:
100°C +  0.768°C = 100.768°C ≈ 100.8°C

The answer is C.

Atomicity occurs to prevent updates of the database occurring only partially, which can cause greater problems than rejecting the whole series outright.some are monatomic, diatomic, triatomic etc because it shows the number of atoms. for example, monatomic means it contains only one atom.