How many ml of a 0.50 m nacl solution are required to prepare 1.00 l of a 0.0050 m nacl solution?

The number  of ml  that are    required  to  prepare 1.00  L   of  0.0050 M NaCl  solution  is 10  mL

 calculation

This  is  calculated using   m1V1  = M2V2 formula  where

M1( molarity 1) = 0.50 M

V1( volume 1)  = ?

M2 ( molarity 2) = 0.0050 M

V2( volume 2)  = 1.00 L

make   V1  the   subject  of the  formula  by  diving both side  by  M1

V1  is  therefore= m2V2/M1

V1 =(0.0050 M x 1.00 L)  / 0.50 M = 0.01 L

convert 0.01 L  to  ml

1L  = 1000   ml

0.01 L  =?  Ml

by cross  multiplication

(0.01 L  x 1000 ml) / 1 L = 10 Ml

idk i'm not smart

explanation:

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