Calculate delta e when 33.0 g of carbon dioxide sublimes at 77.0 k and 1 atm

To solve this problem, we establish the general energy balance:

ΔE = ΔU + ΔKE + ΔPE 
ΔE = Q + W

Q + W = ΔU + ΔKE + ΔPE

In this case, ΔKE and ΔPE are both zero or negligible.

Given:

m = 33.0 grams of CO2
Tsub = 77 K
P = 1 atm

ΔE = Q + W
ΔE = mCpΔT + ΔPV

solve for mCpΔT, find the value of Cp for CO2, then solve for Q. Next, solve for W using the ideal gas law. Add the two values and that will be the value of the delta E.