Given that the density of water is 0.975 g/ml and that 171 g of sucrose (molar mass: 342.30 g/mol) is dissolved in 512.85 ml of water at 80°c, what is the molality of this solution?

1 molal

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

where,

n= moles of solute

  = weight of solvent in g

Putting in the values we get:

Thus molality of solution will be 1 molal.

explanation:

i think option no d is the correct answer

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3