A50 l cylinder is filled with argon gas to a pressure of 10130.0 kpa at 300°c. how many moles of argon gas does the cylinder contain? (given: r = 8.314 l∙kpa/k∙mol)

In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

Given 
P = 10130.0 kPa 
V = 50 L
T = 300 degree celcius + 273.15 = 573.15 K
R = 8.314 L. kPa/K.mol

Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT                      PV
       --->    n =
 RT     RT                       RT

          10130.0 kPa  x 50 L
n=
       8.314 L. kPa/K.mol  x 573.15 K
             506,500 
  =  
         4,765.17  mol K

=106.29 mol Ar

So the moles of argon gas is 106.29 moles 

It conforms what ever surface its in.