"n2(g effuses at a rate that is times that of br2(g under the same conditions."

effuses at a rate that is 2.38 times that of

Explanation:

We have two components: and . We need to compare the rate of effusion under the same conditions.

According to the Graham effusion law: if we have two components Component 1 (C1) and Component 2 (C2), with Molecular Weights M1 and M2 respectively. They will have a rate of effusion V1 and V2 respectively as follows:

Now, we will replace for our components:

Component 1 - Nitrogen  

Component 2 - Bromine

Molecular weight Nitrogen M1 = M() = 28 g/mol

Molecular weight Bromine M2 =M( Bromine ) = 159 g/mol

After that, we should replace the values:  

As V1 is the effusion rate of Nitrogen and V2 is the effusion rate of Bromine. We can reorganize the equation:

The conclusion is that V1 is 2.38 times V2.

It means effuses at a rate that is 2.38 times that of .

43.452

step-by-step explanation:

284 times .153 = 43.452

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