How many molecules are present in 1296 g of dinitrogen pentoxide (n2o5)?

1.199 × 1024
7.2269 × 1025
7.2269 × 1024
1.199 × 1023
7.2269 × 1023

Solve for the molecules present in 1296 g of dinitrogen pentoxide (N2O5)

The molar mass of N2O5 is 108 g/mol. 

1296g of N2O5 has 1296 / 108 = 12 moles. 

1 mole contains 6.022 x 10^23 molecules. 

6.022 x 10^23 x 12 = 7.226 x 10^24 

Therefore, there are 7.226 septillion ( 7.226 x 10^24 ) molecules in 1296g of dinitrogen pentoxide.

sry but any answer choices