How many molecules are in 0.400 moles of. n2o5?

               2.40 × 10²³ Molecules of N₂O₅

Explanation:

As we know 1 mole of any substance contains 6.022 × 10²³ particles (also called as Avogadro's Number). Therefore, the relation between moles and number of particles can be written as,

             Moles  =  Number of Particles ÷ 6.022 ×10²³ Particles.mol⁻¹

For the molecules of Dinitrogen pentoxide (N₂O₅) it can be written as,

             Moles  =  Number of Molecules ÷ 6.022 ×10²³ Molecules.mol⁻¹

Rearranging for Number of Molecules,

             Number of Molecules  =  Moles × 6.022 ×10²³ Molecules.mol⁻¹

Putting value of Moles,

             Number of Molecules  =  0.400 mol × 6.022 ×10²³ Molecules.mol⁻¹

             Number of Molecules  =  2.40 × 10²³ Molecules of N₂O₅

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.