What happens when magnesium reacts with iodine to make magnesium iodide?

Explanation:

Atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2. On the other hand, atomic number of iodine is 53 and its electronic configuration is .

Hence, there are 7 valence electrons in an iodine atom and there are 2 valence electrons in a magnesium atom.

So, one atom of iodine requires one electron from a donor atom to complete its octet. But one magnesium atom contains two valence electrons.

Therefore, one magnesium atom will combine with two iodine atoms to result in the formation of magnesium iodide as follows.  

Therefore, an ionic bond will be formed when  magnesium reacts with iodine to make magnesium iodide.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

the answer is c. nacl