What is the volume of 0.04 mol of a gas at 0.9 kpa and 20°c?
a. 108 l
b. 14.8 l
c. 87.5 l
d. 7.4 l

The correct answer is option A.

Explanation:

Pressure of the gas ,P=  0.9 kPa = 0.008882 atm

1 kPa = 0.0098 atm

Number of moles gases = n  = 0.04 mol

Temperature of the gas ,T =20°C = 293 K

Volume of the gas = V

Using An Ideal gas equation:

PV=nRT

Hence, the correct answer is option A.

the answer is b & c i believe : )

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole