The reaction for the combustion of benzene is: 2c6h6 + 15o2 → 12 co2 +6 h2o. how moles of o2 are required to produce 130 g co2 in the presence of excess c6h6?

a.2.36
b.2.95
c.3.69
d.5.80

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.