What is the concentration of a solution made by diluting 85 ml of 6.0 m hcl to a final volume of 750 ml?

We can use this formula for dilutions to find the new concentrationM₁v₁ = M₂v₂
We can use mL for volume as they will cancel out on both sides even though molarity is moles/liter
(6.0M)*(85mL)=(M₂)*(750mL)M₂ = 0.68
The concentration of a solution after you dilute it is 0.68 M.

The answer is b. because when it leaves the bat, its bringing motion on where its going.

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters