There are 342 g of sucrose in 1.00 mol of sucrose. what is the molar concentration (molarity) of a solution containing 171 g sucrose in 0.750 l solution?

The answer is 0.67 M

Explanation:

Sucrose solution molarity=

You have to divide the mass of sucrose (171 g) by the molecular weight of sucrose (342 g/mol) and then divide the result by the volume in liters (0.750 L) as follows:

Molarity= x

Molarity= 0.666 mol sucrose/L

Molarity= 0.67 M

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atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer