C2h4(g) + h2o(g) ⇌ c2h5oh

if 14g of ethene reacts with excess steam to produce 17.25g of ethanol, what is the percentage yield of the reaction

Molecular wt if ethene = 28 g/mol
take 14 ÷ 28 = 0.5 mol
since there is a 1:1 ratio between ethene and ethanol one should produce 0.5 mol

MW ethanol = 46
0.5 × 46 = 23 g should be produced.

17.25/23 = 0.75 = 75% Percent yield

Sorry i dont understand the question can you rephase it?