Acetic acid is a polar molecule and can form hydrogen bonds with water molecules. therefore, it has high solubility in water. yet acetic acid is also soluble in benzene (c6h6, a nonpolar solvent that lacks the ability to form hydrogen bonds. a solution of 3.8g of ch3cooh in 80g of c6h6 has a freezing point of 3.5 degrees celsius. calculate the molar mass of the solute and suggest what it's structure might be.

Colligative properties calculations are used for this type of problem. Calculations are as follows:

Look up the freezing point of benzene, then delta T = f.p.=3.5 = Kf*m 
Solve for molality. 

molality = moles/kg solvent 
Solve for moles. 

moles acetic acid = grams acetic acid/molar mass acetic acid 
Solve for molar mass. You would expect to find 60 for the molar mass CH3COOH.

answer by yourhope:

how do models compare to real-world objects?

d. most models represent a real-world object in a simpler way.

: )

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.