Chemistry, 30.01.2020 07:02 samanthabutryn

What is the mass in grams of 13.06 ml of acetone
acetone (fingernail-polish remover) has a density of 0.7857 g/cm3

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Answer from: yesseniaroman21

Answer : The mass of acetone will be, 10.26 grams.

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

$Density=\frac{Mass}{Volume}$

Given :

Density of acetone = 0.7857g/cm^3=0.7857g/mL

Volume = 13.06 mL

Now put all the given values in the above formula, we get the mass of acetone.

$0.7857g/mL=\frac{Mass}{13.06mL}$

Mass=10.26g

Therefore, the mass of acetone will be, 10.26 grams.

Answer from: Quest

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

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What is the mass in grams of 13.06 ml of acetone
acetone (fingernail-polish remover) has a de...